Log x is negative so when will you take anti log of that number the answer will be in the form power like

(1234 × 10^ any number ) in this form
So to write accurate answer we will subtract the number greather that of characteristic
And when we do something in math we must cancel it too so that’s why subtract and add that number

In ch 4 in completing square questions we do the same thing we add and subtract the number we have added in the question to complete the square

I think That question is having some mistakes. I am doing only incorrect part. Just check and let me know is it ok for all…?
= 0.0899 + ( -0.1565) – ( -2.1249) – (3.1065)
= 0.0899 – 0.1565 + 2.1249 – 3.1065
= – 1.0482

There is mistake in Q.03 you have write there -q/10(0.6990) but in the second step you wrote -q(0.6996) this is a mistake but I have corrected it in my copy

Author April 10, 2022

There is no mistake found in it. 10 goes to left and multiply with it.

There’s a little mistake in Q1 part vi (6)
log x=-1+1-0.2056
log x=-1+79144 👈 this is wrong step
log x= 1.7944
Next step and answer is correct but that one is mistake
THANKS

Bhai ap nai Q1 kay parts kay answers kay steps zyada tar 2 2 times same steps likhay hai jis ki waja say answer bohot long hogia hai. Kindly correct it.

This website is helpless and enemy of
students. How will students learn to take logarithm of the value in future. They only copy from website and write in their neat registers. What will they do in examinations. Anyways, agar yai website na hoti toh mai ajj fail hota😅😅🤣🤣🤣

in Q no 1 part 2 we had to find antilog of 0.999 and the ans given by calculator is 9.977 and the ans you have written is 1.259 can you please tell me what am i doing wrong in the question ?

Literally I am preparing for my per
Board exams and this website is helping me a lot .
Thank you author for doing hard work for
us .
May God bless you .🙂

It’s very easy method to solve question

They are good but I have a little confusion in part 5 of Qs no 1 in the ending steps before taking the antilog

Log x is negative so when will you take anti log of that number the answer will be in the form power like

(1234 × 10^ any number ) in this form

So to write accurate answer we will subtract the number greather that of characteristic

And when we do something in math we must cancel it too so that’s why subtract and add that number

In ch 4 in completing square questions we do the same thing we add and subtract the number we have added in the question to complete the square

I hope you have got it

nice job

True

I think That question is having some mistakes. I am doing only incorrect part. Just check and let me know is it ok for all…?

= 0.0899 + ( -0.1565) – ( -2.1249) – (3.1065)

= 0.0899 – 0.1565 + 2.1249 – 3.1065

= – 1.0482

There is no mistake found in it.

There is mistake in Q.03 you have write there -q/10(0.6990) but in the second step you wrote -q(0.6996) this is a mistake but I have corrected it in my copy

There is no mistake found in it. 10 goes to left and multiply with it.

It’s good to helping me out in exams .🙂👌

Good mathematics

GOOD MATHEMATICS

very good helps a lot

Helpful in this #Covid situation veery much thanjs to the author appreciating your work

very helpfull

nice bro i was just confused by this doneby them

hey thanks authour your notes are the best and the help me alot

there is a mistake in Q NO 03 in last steps please check it.

There is no mistake found in it.

Kindly mention the mistake.

There’s a little mistake in Q1 part vi (6)

log x=-1+1-0.2056

log x=-1+79144 👈 this is wrong step

log x= 1.7944

Next step and answer is correct but that one is mistake

THANKS

I’ve corrected the mistake. Thanks for the correction.Gud ….help me a lot

Not at all

Great👌🏻☺

NICE NOTES BUT YOU NEED TO CHANGE THE STYLE OF THE PAGE BECAUSE IT ISN’T GOOD

There is a mistake of the numbers in question no 1 part 8 in last 4 rows.

ok, we’ll check it.

Bhai ap nai Q1 kay parts kay answers kay steps zyada tar 2 2 times same steps likhay hai jis ki waja say answer bohot long hogia hai. Kindly correct it.

This website is helpless and enemy of

students. How will students learn to take logarithm of the value in future. They only copy from website and write in their neat registers. What will they do in examinations. Anyways, agar yai website na hoti toh mai ajj fail hota😅😅🤣🤣🤣

in Q no 1 part 2 we had to find antilog of 0.999 and the ans given by calculator is 9.977 and the ans you have written is 1.259 can you please tell me what am i doing wrong in the question ?

There’s a mistake in Q#1 Vii

You didn’t put “Log” in “taking log on both sides”

Okay, we’ll check it.

This website is sooo good

There is a problem in Q1 part 5 in log of 1.23 it is written 0.8999 while it is 0.0899

ok, we’ll check it.

Literally I am preparing for my per

Board exams and this website is helping me a lot .

Thank you author for doing hard work for

us .

May God bless you .🙂